3x^(4/3)+5x^(2/3)-2=0

Solution for 3x^(4/3)+5x^(2/3)-2=0 equation:

x in (-oo:+oo)

3*x^(4/3)+5*x^(2/3)-2 = 0

t_1 = x^(2/3)

3*t_1^2+5*t_1^1-2 = 0

3*t_1^2+5*t_1-2 = 0

DELTA = 5^2-(-2*3*4)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)-5)/(2*3) or t_1 = (-49^(1/2)-5)/(2*3)

t_1 = 1/3 or t_1 = -2

t_1 = -2

x^(2/3)+2 = 0

1*x^(2/3) = -2 // : 1

x^(2/3) = -2

( -2 < 0 i 2/3 in (0:1) ) => x naleu017Cy do O

t_1 = 1/3

x^(2/3)-1/3 = 0

1*x^(2/3) = 1/3 // : 1

x^(2/3) = 1/3

x^(2/3) = 1/3 // ^ 3

x^2 = 1/27 // ^ 1/2

abs(x) = (1/27)^(1/2)

x = (1/27)^(1/2) or x = -(1/27)^(1/2)

x in { (1/27)^(1/2), -(1/27)^(1/2) }